PRANDTL

Excel Usage

=PRANDTL(Cp, k, mu, nu, rho, alpha)

• Cp (float, optional, default: null): Heat capacity [J/kg/K]
• k (float, optional, default: null): Thermal conductivity [W/m/K]
• mu (float, optional, default: null): Dynamic viscosity [Pa*s]
• nu (float, optional, default: null): Kinematic viscosity [m^2/s]
• rho (float, optional, default: null): Density [kg/m^3]
• alpha (float, optional, default: null): Thermal diffusivity [m^2/s]

Returns (float): Prandtl number [-]

Examples

Example 1: Prandtl number with heat capacity, thermal conductivity, and dynamic viscosity

Inputs:

Cp	k	mu
1637	0.01	0.00000461

Excel formula:

=PRANDTL(1637, 0.01, 0.00000461)

Expected output:

0.75466

Example 2: Prandtl number with kinematic viscosity and thermal diffusivity

Inputs:

nu	alpha
6.3e-7	9e-7

Excel formula:

=PRANDTL(6.3e-7, 9e-7)

Expected output:

0.7

Example 3: Prandtl number with heat capacity, thermal conductivity, kinematic viscosity, and density

Inputs:

Cp	k	nu	rho
1637	0.01	6.4e-7	7.1

Excel formula:

=PRANDTL(1637, 0.01, 6.4e-7, 7.1)

Expected output:

0.74385

Example 4: Prandtl number for different fluid

Inputs:

Cp	k	mu
2000	0.015	0.000005

Excel formula:

=PRANDTL(2000, 0.015, 0.000005)

Expected output:

0.66667

Python Code

from fluids.core import Prandtl as fluids_Prandtl

def prandtl(Cp=None, k=None, mu=None, nu=None, rho=None, alpha=None):
    """
    Calculate the Prandtl number.

    See: https://fluids.readthedocs.io/fluids.core.html#fluids.core.Prandtl

    This example function is provided as-is without any representation of accuracy.

    Args:
        Cp (float, optional): Heat capacity [J/kg/K] Default is None.
        k (float, optional): Thermal conductivity [W/m/K] Default is None.
        mu (float, optional): Dynamic viscosity [Pa*s] Default is None.
        nu (float, optional): Kinematic viscosity [m^2/s] Default is None.
        rho (float, optional): Density [kg/m^3] Default is None.
        alpha (float, optional): Thermal diffusivity [m^2/s] Default is None.

    Returns:
        float: Prandtl number [-]
    """
    try:
      # Check that at least one valid parameter set is provided
      if Cp is not None and k is not None and mu is not None:
        Cp_val = float(Cp)
        k_val = float(k)
        mu_val = float(mu)
        return float(fluids_Prandtl(Cp=Cp_val, k=k_val, mu=mu_val))
      if nu is not None and alpha is not None:
        nu_val = float(nu)
        alpha_val = float(alpha)
        return float(fluids_Prandtl(nu=nu_val, alpha=alpha_val))
      if Cp is not None and k is not None and nu is not None and rho is not None:
        Cp_val = float(Cp)
        k_val = float(k)
        nu_val = float(nu)
        rho_val = float(rho)
        return float(fluids_Prandtl(Cp=Cp_val, k=k_val, nu=nu_val, rho=rho_val))
      return "Error: One of the following parameter sets must be provided: (Cp, k, mu), (nu, alpha), or (Cp, k, nu, rho)"
    except Exception as e:
      return f"Error: {str(e)}"

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